Integrand size = 16, antiderivative size = 75 \[ \int \frac {(a+b x)^3 (A+B x)}{x^7} \, dx=-\frac {a^3 A}{6 x^6}-\frac {a^2 (3 A b+a B)}{5 x^5}-\frac {3 a b (A b+a B)}{4 x^4}-\frac {b^2 (A b+3 a B)}{3 x^3}-\frac {b^3 B}{2 x^2} \]
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Time = 0.02 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {77} \[ \int \frac {(a+b x)^3 (A+B x)}{x^7} \, dx=-\frac {a^3 A}{6 x^6}-\frac {a^2 (a B+3 A b)}{5 x^5}-\frac {b^2 (3 a B+A b)}{3 x^3}-\frac {3 a b (a B+A b)}{4 x^4}-\frac {b^3 B}{2 x^2} \]
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Rule 77
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {a^3 A}{x^7}+\frac {a^2 (3 A b+a B)}{x^6}+\frac {3 a b (A b+a B)}{x^5}+\frac {b^2 (A b+3 a B)}{x^4}+\frac {b^3 B}{x^3}\right ) \, dx \\ & = -\frac {a^3 A}{6 x^6}-\frac {a^2 (3 A b+a B)}{5 x^5}-\frac {3 a b (A b+a B)}{4 x^4}-\frac {b^2 (A b+3 a B)}{3 x^3}-\frac {b^3 B}{2 x^2} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.92 \[ \int \frac {(a+b x)^3 (A+B x)}{x^7} \, dx=-\frac {10 b^3 x^3 (2 A+3 B x)+15 a b^2 x^2 (3 A+4 B x)+9 a^2 b x (4 A+5 B x)+2 a^3 (5 A+6 B x)}{60 x^6} \]
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Time = 0.39 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.88
method | result | size |
default | \(-\frac {a^{3} A}{6 x^{6}}-\frac {a^{2} \left (3 A b +B a \right )}{5 x^{5}}-\frac {3 a b \left (A b +B a \right )}{4 x^{4}}-\frac {b^{2} \left (A b +3 B a \right )}{3 x^{3}}-\frac {b^{3} B}{2 x^{2}}\) | \(66\) |
norman | \(\frac {-\frac {b^{3} B \,x^{4}}{2}+\left (-\frac {1}{3} b^{3} A -a \,b^{2} B \right ) x^{3}+\left (-\frac {3}{4} a \,b^{2} A -\frac {3}{4} a^{2} b B \right ) x^{2}+\left (-\frac {3}{5} a^{2} b A -\frac {1}{5} a^{3} B \right ) x -\frac {a^{3} A}{6}}{x^{6}}\) | \(74\) |
risch | \(\frac {-\frac {b^{3} B \,x^{4}}{2}+\left (-\frac {1}{3} b^{3} A -a \,b^{2} B \right ) x^{3}+\left (-\frac {3}{4} a \,b^{2} A -\frac {3}{4} a^{2} b B \right ) x^{2}+\left (-\frac {3}{5} a^{2} b A -\frac {1}{5} a^{3} B \right ) x -\frac {a^{3} A}{6}}{x^{6}}\) | \(74\) |
gosper | \(-\frac {30 b^{3} B \,x^{4}+20 A \,b^{3} x^{3}+60 B a \,b^{2} x^{3}+45 a A \,b^{2} x^{2}+45 B \,a^{2} b \,x^{2}+36 a^{2} A b x +12 a^{3} B x +10 a^{3} A}{60 x^{6}}\) | \(76\) |
parallelrisch | \(-\frac {30 b^{3} B \,x^{4}+20 A \,b^{3} x^{3}+60 B a \,b^{2} x^{3}+45 a A \,b^{2} x^{2}+45 B \,a^{2} b \,x^{2}+36 a^{2} A b x +12 a^{3} B x +10 a^{3} A}{60 x^{6}}\) | \(76\) |
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Time = 0.22 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.97 \[ \int \frac {(a+b x)^3 (A+B x)}{x^7} \, dx=-\frac {30 \, B b^{3} x^{4} + 10 \, A a^{3} + 20 \, {\left (3 \, B a b^{2} + A b^{3}\right )} x^{3} + 45 \, {\left (B a^{2} b + A a b^{2}\right )} x^{2} + 12 \, {\left (B a^{3} + 3 \, A a^{2} b\right )} x}{60 \, x^{6}} \]
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Time = 0.85 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.09 \[ \int \frac {(a+b x)^3 (A+B x)}{x^7} \, dx=\frac {- 10 A a^{3} - 30 B b^{3} x^{4} + x^{3} \left (- 20 A b^{3} - 60 B a b^{2}\right ) + x^{2} \left (- 45 A a b^{2} - 45 B a^{2} b\right ) + x \left (- 36 A a^{2} b - 12 B a^{3}\right )}{60 x^{6}} \]
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Time = 0.18 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.97 \[ \int \frac {(a+b x)^3 (A+B x)}{x^7} \, dx=-\frac {30 \, B b^{3} x^{4} + 10 \, A a^{3} + 20 \, {\left (3 \, B a b^{2} + A b^{3}\right )} x^{3} + 45 \, {\left (B a^{2} b + A a b^{2}\right )} x^{2} + 12 \, {\left (B a^{3} + 3 \, A a^{2} b\right )} x}{60 \, x^{6}} \]
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Time = 0.29 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00 \[ \int \frac {(a+b x)^3 (A+B x)}{x^7} \, dx=-\frac {30 \, B b^{3} x^{4} + 60 \, B a b^{2} x^{3} + 20 \, A b^{3} x^{3} + 45 \, B a^{2} b x^{2} + 45 \, A a b^{2} x^{2} + 12 \, B a^{3} x + 36 \, A a^{2} b x + 10 \, A a^{3}}{60 \, x^{6}} \]
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Time = 0.05 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.97 \[ \int \frac {(a+b x)^3 (A+B x)}{x^7} \, dx=-\frac {x^2\,\left (\frac {3\,B\,a^2\,b}{4}+\frac {3\,A\,a\,b^2}{4}\right )+x\,\left (\frac {B\,a^3}{5}+\frac {3\,A\,b\,a^2}{5}\right )+\frac {A\,a^3}{6}+x^3\,\left (\frac {A\,b^3}{3}+B\,a\,b^2\right )+\frac {B\,b^3\,x^4}{2}}{x^6} \]
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